The Lattice We BuildEpisode 15 / Episode 1 had already proved the wall

"Where does \(G\) come from" ── that question was shaped so that it could never have an answer

Episode 1 had already proved the wall After last time, all that remained was "where to get \(G\) itself."
Going to dig there, my hand stops ── this question is not well posed.
I should have applied what Episode 1 confirmed to my own question. A quantity with dimensions cannot be predicted.
Fix it and you get \(\alpha_G=5.906\times10^{-39}\). And this one does have a mechanism.

Tools needed: Episode 1 (dimensions and dimensionless quantities), logarithms, exponentials The core of this episode: nineteen orders come out of \(1/57\)

A door closed in Episode 13 and another in Episode 14. What remained was \(G\) itself.
Going to dig, I hit a wall at once. And that wall was not built this time ── it was the one I had proved myself back in Episode 1. A quantity with dimensions changes value when you change units. So "why does \(G\) have this value" has no answer.
Fix the question and things move. And the fixed form has a surprisingly straightforward mechanism ── nineteen orders of smallness come out of the unremarkable number \(1/57\).
This episode is the fifth return to Episode 1. But this time we did not hit the wall; we found out what the wall is.

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01Put my own question through Episode 1

What Episode 1 did was brute-force dimensional analysis. It enumerated every dimensionless ratio buildable from 25 physical quantities (162,931 of them) and looked for ones landing on meaningful-looking values ── the result was \(p=0.67\): essentially all coincidence.

Of what that episode confirmed, this is the part that matters now.

WHAT EPISODE 1 CONFIRMED

The "value" of a quantity with dimensions carries no physical information. Because changing units changes it. Physics can only speak about dimensionless quantities.

Apply that to my own question.

questionwell posed?
why does \(G=6.674\times10^{-11}\) have this valueno. change units and it can be made 1
why is the Planck length \(1.6\times10^{-35}\) mno. same reason
why is \(Gm_p^2/\hbar c\) equal to \(5.9\times10^{-39}\)yes

At the end of Episode 14 I wrote "all that remains is where to get \(G\) itself," but that phrasing itself was not up to the job. What has to be got is not \(G\).

I HAD STEPPED IN THE SAME TRAP IN EPISODE 12 Episode 12 wrote that "the cell side \(a\) and the states per cell \(q\) are not determined individually; only \(\log q/a^2\) is." That is exactly this structure. \(a\) carries dimensions, so it is not determined. Only the dimensionless combination is.
Episode 14 wrote "only the ratio of \(\sigma\) to \(G\) is determined." Also the same. Three times in a row I met the same shape, and never fixed the question.
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02The fixed form ── gravity's fine-structure constant

Electromagnetism has \(\alpha=e^2/4\pi\varepsilon_0\hbar c\simeq1/137\). Do the same for gravity ──

CALCULATION $$\alpha_G=\frac{Gm_p^2}{\hbar c}$$
numbers (CODATA)

\(G=6.67430\times10^{-11}\), \(m_p=1.67262192369\times10^{-27}\,\mathrm{kg}\), \(\hbar=1.054571817\times10^{-34}\), \(c=2.99792458\times10^8\)

$$\alpha_G=5.9061\times10^{-39}$$
the same thing, written as a mass ratio
$$m_{\rm Pl}=\sqrt{\frac{\hbar c}{G}}=2.176434\times10^{-8}\,\mathrm{kg}=1.2209\times10^{19}\,\mathrm{GeV}$$ $$\frac{m_p}{m_{\rm Pl}}=7.6851\times10^{-20},\qquad \left(\frac{m_p}{m_{\rm Pl}}\right)^2=5.9061\times10^{-39}\;\checkmark$$

So "why is gravity so weak" is the same question as "why is the proton nineteen orders lighter than the Planck mass". Not a story about \(G\) but a story about the hierarchy of masses.

And this form has a mechanism.

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03Where do the nineteen orders come from ── dimensional transmutation

The proton's mass does not come from the quark masses. Almost all of it is the energy of the strong interaction. And that scale \(\Lambda_{\rm QCD}\) is a number that was never in the theory to begin with.

The QCD Lagrangian has no mass scale. All it has is the dimensionless coupling \(\alpha_s\). But \(\alpha_s\) runs with energy and diverges at some low energy. Where it diverges is \(\Lambda_{\rm QCD}\) ── a quantity with dimensions born from a dimensionless number. This is called dimensional transmutation.

ONE-LOOP RUNNING
$$\frac{1}{\alpha_s(\mu)}=\frac{b_0}{2\pi}\ln\frac{\mu}{\Lambda},\qquad b_0=11-\frac23n_f$$

Solve this for \(\Lambda\) ──

$$\boxed{\;\Lambda=\mu\,\exp\!\left(-\frac{2\pi}{b_0\,\alpha_s(\mu)}\right)}$$

There is a \(1/\alpha_s\) inside the exponent. So even with \(\alpha_s\) an unremarkable number around \(1/50\), \(\Lambda/\mu\) can become fantastically small.

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04Doing it

There is only one input ── the measured \(\alpha_s(M_Z)=0.1179\). From it we get \(\Lambda\) and run up to the Planck scale.

CALCULATION ── from one measured value to nineteen orders
# input: alpha_s(M_Z) = 0.1179, M_Z = 91.1876 GeV, n_f = 5, one loop
  b0 = 11 - 2*5/3 = 7.6667

# downward: get Lambda
  Lambda = M_Z exp(-2pi/(b0 * 0.1179)) = 0.0873 GeV = 87.3 MeV

# upward: extend the same straight line to the Planck scale
  ln(M_Pl/Lambda) = ln(1.2209e19 / 0.0873) = 46.39
  alpha_s(M_Pl)   = 2pi/(b0 * 46.39) = 0.01767 = 1/56.6

# read off the hierarchy
  Lambda / M_Pl = exp(-46.39) = 7.15e-21
  observed m_p/M_Pl            = 7.685e-20
  offset = 10.7  ←  m_p/Lambda = 938 MeV / 87.3 MeV = 10.7

  => twenty orders of hierarchy came out of the number 1/56.6.
     the remaining offset is only "how many times Lambda the proton mass is". O(10) hadron physics.
THIS IS NOT A PREDICTION That the offset equals \(m_p/\Lambda\) is an identity, not an independent verification. What this calculation did is translation, not prediction ── it rewrote "why \(10^{-20}\)" as "why \(1/\alpha_s(M_{\rm Pl})\simeq57\)."
But it is a meaningful rewriting. A twenty-order mystery has become one number of order \(O(50)\). The size of the thing to be explained has dropped from exponential to linear.
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05The lever of the exponent

Being inside an exponent means the sensitivity is exponential too. Try moving the figure.

Figure: \(1/\alpha_s\) is a straight line in \(\ln\mu\). Where it crosses zero is \(\Lambda_{\rm QCD}\). Change the slope at the Planck scale (= the value of the coupling) a little and the crossing moves by orders of magnitude. The red point is the measured \(\alpha_s(M_Z)=0.1179\)
\(1/\alpha_s(\mu)\) measured \(\alpha_s(M_Z)=0.1179\) \(\Lambda\) (where the line crosses zero)
\(1/\alpha_s(M_{\rm Pl})\)\(\ln(M_{\rm Pl}/\Lambda)\)\(\Lambda\)proton mass would be
4536.881180 GeVa proton at the \(10^4\) GeV scale
5040.9819.5 GeVthe 200 GeV scale
56.646.3987.3 MeV938 MeV ✓
6049.175.39 MeVthe 58 MeV scale
6553.270.0895 MeVthe 1 MeV scale

From \(1/50\) to \(1/60\) ── a 20% change moves \(\Lambda\) by four orders.

The mechanism's strength and its weakness come from the same place. It can create smallness because it is exponential. The value is sensitive because it is exponential. You cannot take only one.

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06So what has not been explained?

Let us draw the line honestly.

quantityis there a mechanism?
proton mass / Planck mass (\(10^{-20}\))yes. dimensional transmutation. but \(1/\alpha_s\simeq57\) is an input
\(\alpha_s(M_{\rm Pl})\simeq1/57\) itselfno. that becomes a question about unification
Higgs mass / Planck massno ── this is the real hierarchy problem
the cosmological constant (\(10^{-122}\))no. worse still

The third row matters. The proton is protected; the Higgs is not.

The proton mass is small because QCD's coupling runs only logarithmically, so exponential smallness appears automatically. Nothing was tuned. The Higgs mass squared, by contrast, receives corrections going as the cutoff squared, so keeping it small requires cancellations. There is no automatic answer to "why is it light" ── that is the hierarchy problem.

CONNECTING WITH EPISODE 2 The same picture as anomaly cancellation in Episode 2. Some quantities are protected and some are not. The protected ones (anomaly coefficients, \(\Lambda_{\rm QCD}\)) fix themselves. The unprotected ones (the Higgs mass, the cosmological constant) need tuning or a mechanism.
This series' refrain that "only a binary target carries information" wears, here, the face of "protected by renormalization, or not."
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07Does asymptotic safety give us \(G\)?

It does not. But the way it fails to is suggestive.

Asymptotic safety says the dimensionless coupling \(g=Gk^2\) runs to a fixed point at high energy. Its value in the Einstein–Hilbert truncation is ──

THE REUTER FIXED POINT (EINSTEIN–HILBERT TRUNCATION) $$g_*=0.911,\qquad \lambda_*=0.160,\qquad g_*\lambda_*=0.146$$

Since \(g_*=Gk^2\), \(G(k)=g_*/k^2\). As \(k\to\infty\), \(G\to0\).

What is fixed is not \(G\) but \(Gk^2\). A dimensionless quantity. The low-energy value of \(G\) is set by "where you exit the fixed point," and that is an IR input.

SO IT COMES TO THIS

What asymptotic safety reduces is the number of free parameters. Infinitely many counterterms drop to finitely many (the number of relevant directions). But the one that sets the overall scale always remains.

This is not a defect; it is Episode 1's conclusion itself ── scales cannot be predicted. Only ratios can.

ON THE FIXED-POINT NUMBERS \(g_*=0.911,\ \lambda_*=0.160\) depend on the truncation. Other schemes report values differing by orders, such as \(\lambda_*=1.85,\ g_*=58.73\). Individual values are scheme dependent; what is said to be relatively stable is the product \(g_*\lambda_*\). Here too, what is stable is a dimensionless combination, not a single number.
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08Episode 1, for the fifth time

Let us count. How many times has this series returned to Episode 1 §08's "dimensions get you as far as \(S\propto A\), and only the \(1/4\) refuses"? ──

episodehow it returnedthe reading at the time
Episode 9while forming the conjecturefilling the coefficient needs something to count
Episode 11hunting for the central chargemaybe we are looking in the wrong place
Episode 12after the area law came out by itselfnot even dimensional analysis, and the wall is the same height
Episode 14trying to count degrees of freedomthe coefficient can never come out of matter degrees of freedom
Episode 15trying to dig out \(G\)this wall was the wall Episode 1 proved
WHAT THE FIFTH TIME REVEALED

The \(1/4\) did not come out not because the tools were insufficient. The \(1/4\) is a number that only means anything paired with \(G\), and \(G\) carries dimensions.

The same reason the brute force of Episode 1 failed. It has taken fourteen episodes to apply what I proved back then to my own question.

The wall does not move, but we know what it is ── this is not a wall to climb but the edge of the map. If there is something past the edge, it is not "a way to compute the \(1/4\)" but "a theory that makes the list of dimensionless quantities shorter."

WORK IT BY HAND
  1. Verify by tracking dimensions that \(\alpha_G=Gm_p^2/\hbar c\) is dimensionless.
    show the answer
    \([G]=\mathrm{m^3kg^{-1}s^{-2}}\), \([m_p^2]=\mathrm{kg^2}\), \([\hbar]=\mathrm{J\,s}=\mathrm{m^2kg\,s^{-1}}\), \([c]=\mathrm{m\,s^{-1}}\). The numerator is \(\mathrm{m^3kg\,s^{-2}}\), the denominator \(\mathrm{m^3kg\,s^{-2}}\). They match: dimensionless. The same thing as solving one line of Episode 1's \(D\mathbf a=0\).
  2. If \(1/\alpha_s(M_{\rm Pl})\) rises from \(57\) to \(60\), by what factor does \(\Lambda\) change? Use \(b_0=7.667\).
    show the answer
    \(\ln(M_{\rm Pl}/\Lambda)=\frac{2\pi}{b_0}\cdot\frac{1}{\alpha_s}\), so \(57\to60\) raises the exponent by \(\frac{6.283}{7.667}\times3=2.46\). Hence \(\Lambda\) changes by \(e^{-2.46}=0.086\) ── about one twelfth. A 5% change gives more than an order of magnitude. That is the lever of the exponent.
  3. "Use units where \(G=1\) and the mystery of \(G\) disappears" ── what is wrong with that?
    show the answer
    What disappears is not the mystery but where it is kept. Set \(G=1\) (Planck units) and now the proton mass takes the strange value \(7.7\times10^{-20}\). The dimensionless \(\alpha_G\) does not change under a change of units. So changing units solves nothing ── and at the same time it tells you that what needs solving is \(\alpha_G\). That substitution is exactly what this episode did.

What we learned in this episode

"Where does \(G\) come from" is not well posed. The value of a quantity with dimensions changes with units, so it carries no physical information ── something I had confirmed myself in Episode 1. Episode 12's "only \(\log q/a^2\) is determined" and Episode 14's "only the ratio of \(\sigma\) to \(G\) is determined" made three encounters with the same shape.

The fixed form is \(\alpha_G=Gm_p^2/\hbar c=5.9061\times10^{-39}\). This equals \((m_p/m_{\rm Pl})^2\) (verified numerically). That is, "why is gravity weak" = "why is the proton nineteen orders lighter than the Planck mass." Not a story about \(G\) but about the hierarchy of masses.

And the nineteen orders have a mechanism ── dimensional transmutation. Because \(\Lambda=\mu\exp(-2\pi/b_0\alpha_s)\) puts \(1/\alpha_s\) in the exponent, an unremarkable coupling of order \(1/50\) yields fantastic smallness. From the single measured \(\alpha_s(M_Z)=0.1179\): \(\Lambda=87.3\) MeV, hence \(\alpha_s(M_{\rm Pl})=1/56.6\) and \(\Lambda/M_{\rm Pl}=e^{-46.39}=7.15\times10^{-21}\). The offset of 10.7 against the observed \(m_p/M_{\rm Pl}=7.685\times10^{-20}\) is exactly accounted for by \(m_p/\Lambda=10.7\).

But this is translation, not prediction. That the offset equals \(m_p/\Lambda\) is an identity, not an independent check. What was done is rewriting "why \(10^{-20}\)" as "why \(1/\alpha_s\simeq57\)." It still means something ── the thing to be explained dropped from exponential to linear.

The lever of the exponent. Move \(1/\alpha_s(M_{\rm Pl})\) 20%, from \(50\) to \(60\), and \(\Lambda\) moves four orders. The ability to create smallness and the sensitivity of the value come from the same exponent. You cannot take only one.

Protected quantities and unprotected ones. The proton mass is automatically light thanks to logarithmic running. The Higgs mass receives cutoff-squared corrections and therefore needs cancellations ── the real hierarchy problem. The same picture as anomaly cancellation in Episode 2, with the series' "binary target" appearing this time as "protected by renormalization, or not."

Asymptotic safety does not give \(G\) either. What is fixed is \(g_*=Gk^2\) (\(=0.911\), truncation dependent; other schemes report \(58.73\)). Only dimensionless quantities are fixed, and the one that sets the overall scale always remains. What is reduced is the number of parameters, not the scale.

Episode 1, a fifth time ── and this time it was the identity of the wall. The \(1/4\) did not come out not from a lack of tools but because the \(1/4\) only means anything paired with \(G\), and \(G\) carries dimensions. Not a wall to climb but the edge of the map. What lies past the edge is not "a way to compute the \(1/4\)" but a theory that makes the list of dimensionless quantities shorter.

This document is Episode 15 of the "Lattice We Build" series, a reading piece for high-school and university students who love physics. Where the sister series "That Clicks" explains known physics, this series shows the work itself ── including the realization that I had set the question up wrongly.

Established material: the general facts about dimensional analysis and dimensionless quantities; \(\alpha_G=Gm_p^2/\hbar c\) and the Planck-mass numbers (computed from CODATA 2018 \(G,m_p,\hbar,c\)); the one-loop QCD beta function and \(b_0=11-\frac23n_f\); the generation of \(\Lambda_{\rm QCD}\) by dimensional transmutation; \(\alpha_s(M_Z)=0.1179\) (PDG); the quadratic divergence of the Higgs mass and the hierarchy problem; and the Reuter fixed point of asymptotic safety with the values of \(g_*,\lambda_*\) in the Einstein–Hilbert truncation and their truncation dependence.
The calculations in this article (\(\alpha_G\), the one-loop \(\Lambda\) and \(\alpha_s(M_{\rm Pl})\), the comparison of \(e^{-46.39}\) with observation, the sensitivity table) were carried out and checked by the author from the above. Because a one-loop approximation is used, the value of \(\Lambda\) differs from the standard two-loop-and-beyond value (\(\Lambda^{(5)}_{\overline{\rm MS}}\simeq210\) MeV). This article prioritized internal consistency using only the measured \(\alpha_s(M_Z)\) and the one-loop formula.
The line that "gravity is weak thanks to dimensional transmutation" is itself a known argument (one Wilczek and others have made repeatedly) and is not this article's original claim. On the other hand, the reading that "the \(1/4\) did not come out as a corollary of Episode 1's conclusion" is this series' author's framing. That the horizon's Carrollian theory itself is unconstructed is as stated in Episodes 8, 11 and 12.

Main series: Episode 1Episode 2Episode 3Episode 4Episode 5Episode 6Episode 7Episode 8Episode 9Episode 10Episode 11Episode 12Episode 13Episode 14 | bonus: ── to print, use your browser's "Print" → "Save as PDF."

Print / PDF: ⌘+P (Ctrl+P on Windows). In the figure you can confirm that moving the coupling slightly moves the hierarchy by orders of magnitude.