The Lattice We BuildEpisode 3 / The stage may stay flat

Curvature is a way of keeping the books, not the content of the physics ── how far can we get on a flat stage?

The stage may stay flat Episode 2 showed that spacetime does not need a spacing. So does it need a warp?
The picture that writes gravity as "the speed of light varying from place to place on flat spacetime" is checkmated by the Weyl tensor.
But what was missing was a single word. Supply it and the whole of general relativity stands up on a flat stage.
And beyond that lies a description with no curvature among its basic elements ── holography.

Tools needed: a feel for tensors, conformal transformations, Episode 2 The core of this episode: curvature is a field, not the stage

"Space curves" is relativity's most famous claim and its hardest to swallow. Shown a picture of a weight on a rubber sheet, one nods vaguely and moves on ── plenty of people do exactly that.
Here let us push the straightforward doubt all the way. Does it really have to be curved? Could the stage stay flat, with something happening on top of it?
The conclusion up front ── it could. It holds exactly. But getting there requires diagnosing precisely where the naive approach gets stuck, and supplying exactly one missing thing. And beyond the supplying, a stronger position is waiting.

01First, exactly where it gets stuck

"Gravity is the speed of light varying from place to place on flat spacetime" ── let us start from that picture (the piece that follows this rereading all the way is Bonus ②). It is the approach of positing a refractive index \(n(x)\approx1-2\Phi/c^2\). Light bending, gravitational redshift and the Shapiro delay all come out correctly this way.

Written as a formula, this picture amounts to assuming the following metric.

$$ds^2=\Omega^2(x)\,\eta_{\mu\nu}dx^\mu dx^\nu$$

A flat metric with nothing but a position-dependent scalar factor. This is called conformally flat. And there is an exact criterion.

THE CRITERION

the metric is conformally flat \(\iff\) the Weyl tensor vanishes

That draws the boundary. And the result splits cleanly.

spacetimeWeyl tensorwritable with a scalar alone?
FRW (expanding universe)\(=0\)yes. and exactly
Schwarzschild (a star)\(\ne0\)impossible in principle

The expanding universe really is conformally flat. Move to conformal time and light runs on exact 45° straight lines. That is no accident ── the expanding universe is literally "flat spacetime × a scale factor," and in that sense it is not curved. Your intuition, as far as cosmology goes, is correct as a theorem.

Schwarzschild is different. It is a vacuum solution, so \(R_{\mu\nu}=0\), which means all of the curvature is Weyl curvature.

TRY IT ── curvature that will not vanish $$R_{abcd}R^{abcd}=\frac{48G^2M^2}{c^4r^6}\neq 0$$

this is the tidal force itself

Ricci is zero and yet the curvature invariant is not ── what remains is all Weyl. So it cannot be made conformally flat. However you choose the scalar \(\Omega(x)\), you cannot write down a single star.

Why "light alone" happened to come out right

This is the interesting part. There is a mechanical explanation for why the refractive-index picture only works for "light in a static weak field."

Null geodesics are conformally invariant. The path of light does not change when you multiply by \(\Omega^2\). So as long as the conformal class of the metric is right, light bending is structurally bound to be reproduced.

Which is to say the refractive-index picture is built so as to hit for light. But the parts that a conformal factor cannot squash ── Weyl curvature, the rate of clocks, the orbits of matter ── are untouchable with one scalar.

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02What was missing was a single word

So what is missing? A concrete example makes it obvious in an instant.

Consider frame dragging. Around a rotating body, the time for light to circle clockwise and the time to circle anticlockwise differ (this has been measured).

A scalar \(c(x)\) cannot write this. It has only one value at each point, so it cannot return different answers for different directions.

To write it you need \(c(x,\hat n)\) ── a direction-dependent speed of light. Gravitational waves are the same. A TT polarization stretches one direction and shrinks the orthogonal one. A scalar cannot write anisotropic stretching.

THE MISSING WORD

Something that gives a speed per direction at each point.
Mathematics calls it a tensor field; physics calls it the metric \(g_{\mu\nu}\).

Here you might think "so it was the metric after all. We are just back to curvature." That is exactly what is not so. Here is where the real subject begins.

03Put a tensor field on flat spacetime

General relativity can be constructed as the theory of a self-interacting massless spin-2 field \(h_{\mu\nu}\) living on flat Minkowski spacetime. Gupta (1954), Feynman, Deser (1970).

Deser's argument is the cleanest.

TRY IT ── the series closes

Step 1. On flat spacetime \(\eta_{\mu\nu}\), write a massless spin-2 field \(h_{\mu\nu}\) (a free field).

Step 2. This field couples to the energy-momentum of matter. But the field itself carries energy. So it must couple to itself as well.

Step 3. Add the correction term. That correction term also carries energy, so add again. Iterate.

result

The series closes, and becomes the Einstein equations themselves. And

$$g_{\mu\nu}=\eta_{\mu\nu}+h_{\mu\nu}$$

appears as a consequence, as the "effective metric." It was not assumed at the outset; it came out.

Weinberg showed something stronger still. Any Lorentz-invariant theory of a massless spin-2 particle coupled to a conserved source must, at low energy, become general relativity. Which is to say ──

THE CORE OF THIS EPISODE

The equivalence principle is a conclusion, not an assumption.
You do not need to put "gravitational mass = inertial mass" in by hand. It is derived from the setup of a spin-2 field on flat spacetime.

So "space is not warped; a field on a flat stage merely behaves that way" is not a poetic rephrasing but an exact formulation. Curvature becomes not a property of the stage but a field sitting on the stage.

Figure: the same light bending, booked two ways. Left = "space is curved," right = "space is flat and there is a field." Change the mass with the slider
the light path (identical on both sides) the straight line it would have taken with no mass

The red path does not differ by a single pixel between left and right. The same array is drawn twice. The only difference is how the background is drawn ── on the left the lattice is distorted; on the right the lattice is left square and the field is shown by shading.

What is observed is only the red line. The background lattice is, in both cases, a line you drew on paper; it is not out there in nature.

04Price ① ── the flat background cannot be observed

Let us draw the honest line. This formulation has a strange price.

Nothing couples to \(\eta_{\mu\nu}\) alone. Rulers, clocks and light all measure with \(g=\eta+h\). So you can say "it is really flat," but no experiment detecting that flatness exists even in principle.

A delicate position. Like a preferred frame, but a completely invisible one.

HOWEVER ── which is exactly why it does not catch Episode 2's disease The eighteen orders of fine-tuning seen in Episode 2 arose from a physical preferred frame being amplified by radiative corrections.
The flat background \(\eta_{\mu\nu}\) is different. Since nothing couples to it, it does not act on the renormalization either. What cannot be seen cannot be amplified.
"Safe, and at the same time empty" ── that duality pins down the character of this formulation. Precisely because its physical content is zero, so is its harm.

05Price ② ── it is bad at global structure

One more, and this one is a substantive limitation.

An expansion around a flat background does not cover the interior of a horizon, non-trivial topology, or a closed universe well. The reach of the perturbation series is limited.

The shape of it is "completely right locally, insufficient globally." Try to write the interior of a black hole as \(\eta+h\) and the premise that \(h\) is small collapses.

THE HONEST LINE ── "not fundamental" is not "not real" Whichever formulation you choose, tidal forces can be measured. \(R_{\mu\nu\rho\sigma}\) has observable consequences.
What you are choosing is a way of keeping the books; you are not deleting physics. You are free to say "it is not curved," but not one phenomenon disappears as a result.
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06And it can be solved by finite differences

So far this has been "you may book it that way." But this position has a practical payoff. And it is not a thought experiment ── it is running for real right now.

If the lattice does not distort, you can lay square cells out in space and replace derivatives by differences. For someone who writes programs, this is decisively welcome.

$$\frac{\partial f}{\partial x}\;\longrightarrow\;\frac{f_{i+1}-f_{i-1}}{2\Delta x}$$

And ── numerical relativity does exactly this.

WHAT IS ACTUALLY DONE

Lay a flat orthogonal lattice out in memory. At each point put \(g_{\mu\nu}\) (in practice variables called BSSN or Z4c) as field values. Evolve in time by finite differences.

The lattice never distorts. The curvature is not in the lattice but inside the numbers sitting on the lattice points.

When LIGO detected a black-hole merger, the waveform templates matched against the data were built this way. Curved spacetime, computed on a lattice that does not distort.

And structurally this is Deser's formulation of §03 itself. The stage is flat; the curvature is a field \(h_{\mu\nu}\) on the stage. The formulation and the implementation have the same shape.

That said, the hard parts are not the lattice

Honestly, here is what is hard. The point is that none of it is caused by "the lattice not distorting."

hard partcontent
① foliation (gauge)To take differences you must slice spacetime into "space × time." How you slice is free, but slice it wrong and the lattice points fall into the black hole and the computation blows up. Techniques like 1+log slicing, gamma-driver shift and moving punctures are needed.
② constraint violationThe Einstein equations split into "evolution equations" and "constraints." Finite differences always violate the constraints slightly, and that error grows exponentially. It was only solved by constraint-damping formulations like BSSN, Z4c and generalized harmonic.
③ singularitiesThe numbers diverge at the centre of a black hole. Either cut it out (excision) or dodge it with clever coordinates (punctures).
WHY IT WAS STUCK FOR FORTY YEARS Numerical relativity began in the 1960s, but it only became possible to compute a black-hole binary all the way through in 2005. It took about forty years.
What held it up was ② constraint violation, and neither the lattice nor the finite differences. The very idea of putting a field on a flat lattice was right from the start.

Why this is safe ── Episode 2's distinction does the work

Recall the table from Episode 2. A lattice had two distinct roles: (a) computational tool and (b) basic structure of spacetime.

The lattice of numerical relativity is entirely (a). The spacing \(\Delta x\) is artificial; you refine it and check convergence. Not one word claims "spacetime is made of a lattice."

So Episode 2's eighteen-order fine-tuning problem does not arise at all. Because no preferred frame has been introduced as physics.

THE CORE OF THIS SECTION

"Space does not distort," therefore it can be solved by finite differences ── this is correct, and it is what people actually do.
What is not distorting is the computational lattice; nobody is claiming spacetime is discrete. Which is why it is safe.

07The stronger version ── holography

So far the story has been "rewrite curvature as a field." The flat background remains, merely invisible.

There is a more thoroughgoing position: that neither curvature nor curved spacetime exists as a basic element at all.

In AdS/CFT, the boundary theory has no gravity. And no curvature. It is an ordinary field theory sitting on a fixed flat background. And ──

EMERGENT SPACETIME

The curved bulk spacetime emerges from the entanglement structure of the boundary.
Curvature is not a basic existent but one form of the description of a flat field theory.

This is the strongest version of "no warping of space is needed." In §03 the stage remained, flat; here the very concept of a curved stage disappears from the basic description.

And a lot lines up.

what we wantedin the boundary theory
no warping of space○ a flat fixed background
no spacing of space (Episode 2)○ a continuum field theory
exact Lorentz invariance○ conformally invariant, even
a finite amount of information○ the holographic bound
computable○ an ordinary field theory

This position never touches Episode 2's \(6\times10^{-20}\), nor the eighteen orders of fine-tuning. Because it creates no preferred frame and introduces no spacing.

08The honest line

Finally, what this position is paying.

The only controlled example is AdS. \(\Lambda<0\). But our universe has \(\Lambda>0\). Holography in de Sitter is unsolved, and that is this route's greatest weakness.

"The boundary is flat" is also, in a sense, a choice. The background the boundary theory sits on is fixed, but the reason we may call it "flat" is conformal invariance; in reality only the conformal class is fixed. Here too we are back to bookkeeping.

And the derivations of \(1/4\) and of the Page curve are for special settings. Three-dimensional gravity, JT gravity, supersymmetric and extremal black holes. It is not that the same thing has been done for a general Schwarzschild black hole. We are at the stage of having got through the wall at one spot.

EXERCISES
  1. State in one line why "flat spacetime + a scalar variable speed of light" cannot write Schwarzschild.
    show the answer
    A scalar factor is a conformal transformation, so it can only produce a conformally flat metric. The condition for conformal flatness is that the Weyl tensor \(=0\), but Schwarzschild is a vacuum solution (\(R_{\mu\nu}=0\)) with \(R_{abcd}R^{abcd}=48G^2M^2/c^4r^6\ne0\) ── all of its curvature is Weyl, so it is impossible.
  2. Why, nonetheless, does the refractive-index picture get light bending right?
    show the answer
    Because null geodesics are conformally invariant. The path of light is determined by the conformal class of the metric alone and does not change when multiplied by \(\Omega^2\). So merely tuning the conformal factor is bound to hit for light ── and bound not to hit for anything but light.
  3. In Deser's construction, why does the equivalence principle come out of "a spin-2 field on a flat background"? Give just the thread of it.
    show the answer
    A spin-2 field couples to the conserved energy-momentum tensor. And the field itself carries energy, so it has no choice but to couple to itself with the same strength. "Couples to all energy in the same way" is precisely the equivalence principle, and it is forced by the structure of the iteration. A consequence of consistency, not an assumption.
  4. The flat background \(\eta_{\mu\nu}\) looks like a preferred frame, yet it does not cause Episode 2's fine-tuning problem. Why?
    show the answer
    Episode 2's problem was that a physically detectable preferred frame gets amplified by loop corrections. Nothing couples to \(\eta_{\mu\nu}\) on its own, and every observable goes through \(g=\eta+h\). A structure that cannot be detected does not appear in the renormalization either, so there is nothing to amplify.

What we learned in this episode

A scalar gets stuck. The criterion is the Weyl tensor. The expanding universe has Weyl \(=0\), so it can be written exactly as "flat spacetime × a scale factor," while a star has Weyl \(\ne0\) and cannot be written in principle. The reason light alone comes out right is that null geodesics are conformally invariant.

What was missing was the single word "direction-dependent." Something that gives a speed per direction at each point ── that is a tensor field. Frame dragging and gravitational waves can both be written with it.

Put a tensor field on a flat stage and general relativity stands up. Iterate the self-interaction of a massless spin-2 field and the series closes into the Einstein equations (Gupta–Feynman–Deser). \(g=\eta+h\) is a result, not an assumption. And the equivalence principle comes out as a conclusion (Weinberg).

There are two prices. The flat background cannot be observed in principle (= which is exactly why it does not cause Episode 2's eighteen-order problem). And it does not reach global structure ── horizons, topology.

And the limit of this is holography. The boundary theory has neither gravity nor curvature, and curved spacetime emerges from entanglement. With no warping, no spacing and no preferred frame, you get a finite amount of information and computability. But the only controlled example has \(\Lambda<0\), and our universe has \(\Lambda>0\).

This document is Episode 3 of the "Lattice We Build" series, a reading piece for high-school and university students who love physics. Where the sister series "That Clicks" explains known physics, this series shows the work itself.

Established material: the equivalence of conformal flatness and the vanishing of the Weyl tensor, the conformal flatness of FRW, the Kretschmann invariant of Schwarzschild, the conformal invariance of null geodesics, the reconstruction of general relativity from a spin-2 field on flat spacetime (Gupta 1954, Deser 1970), and that the equivalence principle follows from a massless spin-2 particle (Weinberg). On the other hand, the holographic reading that "curvature is emergent" is a position under research, not an established conclusion. Controlled examples of the duality are limited to asymptotically AdS, and the \(\Lambda>0\) case is unsolved. The figure is schematic: the way the background lattice is distorted is not a quantitative rendering of a metric, and only the light path is a numerical integration using the weak-field refractive index \(n=1+2\mu/r\).

Main series: Episode 1Episode 2|bonus: ① Could physics be written more simply?② How far does "ct = constant" get you? | sister series: Relativity That Clicks ── to print, use your browser's "Print" → "Save as PDF."

Print / PDF: ⌘+P (Ctrl+P on Windows). With the slider in the figure you can confirm that the same path can be booked two ways.