The Universe Is a ComputerEpisode 10 (extended) / The Dimensions of the Four Forces

If you chase "What is the dimension of the weak force and the strong force? Can this formula give it?" without flinching

The Dimensions of the Four Forces We apply \(D=-\dfrac{d\ln F}{d\ln n}\) to the four forces. Gravity and electromagnetism sit at D=2, constant. But the weak force runs 2→∞, the strong force 2→0 — \(D\) is not a single number; it "runs."

Core: everyone starts at D=2 at short range / the only difference is how they run at long range Hook formula: \(D(r)=-\dfrac{d\ln F}{d\ln r}\)

Up through last time we saw that \(F=1/(Cn)^D\) is not a law of force but a ruler for dimension. So what does that instrument read when we point it at nature's four forces? Electromagnetism gives \(D=2\) (\(C\!\approx\!137\)) — the inverse-square law. Then what is the \(D\) of the weak and strong forces? The conclusion, stated up front — you can't get it as a single number. But that isn't a failure; it becomes the cleanest concrete example of last time's "\(D\) runs." Put in a computer person's words, a force is "how far the message called a mediator particle reaches down the wiring called distance without fading." The way it fades differs across the four — that's all.

01First, check the instrument — \(D\) is "the slope of the falloff per distance"

The definition of the ruler was this: as you increase size (here distance \(r\)), by what fraction does the quantity \(F\) shrink? The slope of that on a log–log plot is the dimension \(D\).

The instrument (recap from last time) $$F=\frac{1}{(Cr)^{D}}\quad\Longrightarrow\quad \boxed{\,D=-\frac{d\ln F}{d\ln r}\,}$$

The important thing is that this formula returns \(D\) as a single number only when \(F\) is a clean power law. If \(F\) isn't a power, \(D\) takes a different value at each distance — that is, it runs. The differences among the four forces show up right here. \(C\) is "the reference where the needle points to 1" = the strength of the coupling (for electromagnetism, \(1/\alpha\!\approx\!137\)).

02Massless mediators — so gravity and electromagnetism are "constant" at \(D=2\)

The mediator of electromagnetism (the photon) and of gravity (the graviton) are massless. A massless message reaches arbitrarily far and thins out honestly in 3D space — it spreads over the sphere \(4\pi r^2\), so \(F\propto 1/r^2\). This is a genuine power law, so the instrument answers without hesitation:

Gravity and electromagnetism

\(F=1/r^2\) → \(D=-d\ln F/d\ln r = \mathbf{2}\). No matter how you change the distance, the slope stays 2 — it does not run. This is the "honest inverse square," and your \(C\!=\!137,\ D\!=\!2\) (electromagnetism) is exactly this. Gravity is the same \(D=2\); only \(C\) differs (\(\sim\!10^{39}\), in the table below).

This is the baseline. "Massless mediator = constant \(D=2\)." The remaining two forces are determined by how they deviate and run from this baseline.

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03The weak force — heavy mediators. \(D\) runs from \(2\to\infty\)

The mediators of the weak force (the W and Z particles) are heavy (about 90 times the proton). A heavy message can't fly far and dies off exponentially at a range \(\lambda=\hbar/(Mc)\approx10^{-18}\,\text{m}\) (the Yukawa potential). The force takes the form \(F\sim e^{-r/\lambda}/r^2\). This is not a power law. Even so, apply the instrument \(D=-d\ln F/d\ln r\):

Calculation — apply the instrument to the Yukawa form $$F=\frac{e^{-r/\lambda}}{r^{2}}\;\Longrightarrow\; D(r)=-\frac{d\ln F}{d\ln r}=2+\frac{r}{\lambda}$$

\(\ln F = -\,r/\lambda - 2\ln r\). Differentiating with respect to \(\ln r\) gives \(d\ln F/d\ln r = -\,r/\lambda - 2\). Flip the sign and \(D=2+r/\lambda\).

What "the weak force is weak" really means The weak force is not weak because its coupling is weak (with coupling \(C\!\approx\!30\) it is in fact stronger than electromagnetism's \(137\)). It looks weak because \(D\) runs toward \(\infty\) with distance and cuts the force off — "short range" is just another way of saying "\(D\) diverges." Just as in Episode 8, where we opened \(D\) up to imaginary values, dimension steps outside the integers once you open it all the way to the edge.

04The strong force — it doesn't fall off with distance. \(D\) runs from \(2\to0\)

The strong force is even more extreme. The force between quarks doesn't diminish even as you pull them apart (confinement). The potential is \(V(r)=-a/r+\sigma r\) (the Cornell form) — Coulomb-like \(-a/r\) up close, rising linearly as \(\sigma r\) far away. As a force this is \(F=a/r^2+\sigma\). Apply the instrument:

Calculation — apply the instrument to the confining form $$F=\frac{a}{r^{2}}+\sigma\;\Longrightarrow\; D(r)=-\frac{d\ln F}{d\ln r}=\frac{2a}{a+\sigma r^{2}}=\frac{2}{1+(r/r_0)^{2}}$$

(\(r_0=\sqrt{a/\sigma}\) is the crossover scale, \(\sim\!0.2\,\text{fm}\).)

In the ruler of last time, \(D=0\) is the reading of zero dimension: "changing the size doesn't change the contents." The tube of force (the flux tube) stays twisted and taut; the more you stretch it, the more energy it stores, until it finally snaps and creates a new quark pair — which is why you can't extract a lone quark. The strong force's \(C\approx1\) (\(\alpha_s\!\sim\!1\)) is, literally, the origin of "strong."

Figure: the running dimension \(D(r)\) of the four forces. Horizontal axis is distance (log–log, schematic); vertical axis is the instrument's reading \(D=-d\ln F/d\ln r\). Move the distance cursor with the slider to read off each force's \(D\). Everyone starts at \(D=2\) at the left edge (ultra-short range); gravity and electromagnetism stay flat, the weak force diverges upward, the strong force drops toward zero — they split only at long range. *Horizontal positions are schematic (the real range ratios differ by orders of magnitude). The shapes (2 constant / 2→∞ / 2→0) are real.
Move the slider to read the dimension D of the four forces at that distance.
Gravity (D=2, constant) Electromagnetism (D=2, constant) Weak force (2→∞) Strong force (2→0)
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05The four on one sheet — the core is "everyone is D=2 at short range"

ForceD (short range → long range)C ≈ 1/couplingReason for the falloff (computer-person vocabulary)
Gravity2 (constant)~10³⁹massless mediator → honest power law
Electromagnetism2 (constant)137massless mediator → honest power law
Weak force2 → ∞~30heavy mediator (W/Z) → exponential cutoff
Strong force2 → 0~1confinement → doesn't fall off with distance
The core of this episode

All four forces start from \(D=2\) at ultra-short range. Because in 3+1 dimensions the field a point source sprays out must begin as inverse-square (\(1/r^2\)). The difference is only what happens at long range — the mediator's mass (weak) or confinement from self-interaction (strong). So the correct answer to "what is the dimension of the weak and strong forces?" is "not a single number, but a function that runs from 2 to ∞ / from 2 to 0." You can get it from the formula — but only as a running \(D(r)\).

06The reveal — the instrument is honest, but \(C\)'s role has a seam

Here is the one line you must not blur. For the weak and strong forces, \(D\) does not settle into a single integer. That is not a defect of the instrument; it merely reflects, honestly, the fact that the target isn't a power law — indeed it is fully consistent with last time's "\(D\) runs" philosophy. But there is one more seam that must be stated honestly:

The honest line — \(C\)'s two roles

Last time \(C\) was "the reference scale where the needle points to 1 (the unit of resolution)." In this episode, though, \(C\!=\!137\) is used as "\(1/\alpha\) = the strength of the coupling." Scale and coupling are originally different things. In \(F=1/(Cr)^D\), the \(C\) is the prefactor (the place that absorbs the coupling) and \(D\) is the exponent (the geometry = how the force falls off with distance). Make this division of labor — "\(C\) = coupling / \(D\) = geometry" — explicit, and there's no confusion. Blur them and claim "one formula gave it all," and you are planting a flag.

And there is not a single piece of new physics in this episode. Inverse-square (massless field), the Yukawa potential (exponential cutoff from a massive mediator), asymptotic freedom and confinement (the Cornell form \(-a/r+\sigma r\), the running of \(\alpha_s\)) — all established physics. \(D=-d\ln F/d\ln r\) is the defining formula of dimension, and we simply read it by applying it to known force shapes. The holes that remain — "why does the mediator have that mass?", "where does \(\sigma\) come from (the mass-gap problem)?" — are open problems for physics as a whole, and we don't fill them here. Never say "solved" — that is the rule of the whole series.

Practice problems (solvable from this one sheet)
  1. Answer in one line: "Is the dimension of the weak force 2? Or some other number?"
    Show the answer
    "Not a single number." Inside the range, \(D\to2\) (just like electromagnetism), but outside the range \(D=2+r/\lambda\to\infty\), it runs. So you can't answer with a fixed integer — the right answer is a running function.
  2. What does \(D=0\) mean for the strong force?
    Show the answer
    The force doesn't fall off as you change the distance (\(F\to\sigma\) = constant). On a log–log plot, zero slope = a horizontal line. A reading of zero dimension corresponds to "changing the size doesn't change the contents," which is confinement (the flux tube) itself. That's why a quark can't be extracted on its own.
  3. What is the one thing common to all four forces?
    Show the answer
    Every one starts from \(D=2\) at ultra-short range (a point source in 3+1 dimensions begins as inverse-square). The difference is only in how they run at long range — gravity and electromagnetism stay at 2, weak goes to ∞, strong goes to 0. \(C\) (the coupling) is a separate axis, differing per force: 137 / 30 / 1 / 10³⁹.

SummaryEach force "runs" its dimension differently

Apply the instrument \(D=-d\ln F/d\ln r\) to the four forces and every one starts at \(D=2\) at ultra-short range. Gravity and electromagnetism have massless mediators and stay at constant \(D=2\), inverse-square. The weak force, with heavy mediators, runs \(D=2+r/\lambda\to\infty\) (which is why "short range" = "weak"). The strong force, with confinement, runs \(D=2/(1+(r/r_0)^2)\to0\) (which is why it "doesn't fall off with distance" = "strong").

So the honest answer to "what is the dimension of the weak and strong forces?" is not a single integer but a running function. You can get it from the formula — but as a concrete case of last time's "\(D\) runs." Make explicit that \(C\) (coupling) and \(D\) (geometry) are separate axes, and leave "why that mass, why that \(\sigma\)?" open as a hole in physics as a whole — keep those two disciplines, and you move forward with a signpost, not a flag.

← Episode 9: The Formula of Information and the Formula of Physics To the contents Episode 11: D=2 Is on the Blade's Edge →
This document is Episode 10 (extended) of the series "The Universe Is a Computer." The inverse-square law (the \(1/r^2\) of a massless field), the Yukawa potential (exponential cutoff \(e^{-r/\lambda}\) from a mediator of mass \(M\), with \(\lambda=\hbar/Mc\)), the Cornell potential \(V=-a/r+\sigma r\) and QCD's asymptotic freedom, confinement, and the running of the coupling \(\alpha_s\), the electroweak coupling \(\alpha_w\), the fine-structure constant \(\alpha\!\approx\!1/137\), and gravity's dimensionless coupling \(\alpha_G\!\sim\!10^{-39}\) are all established physics. \(D=-d\ln F/d\ln r\) is the defining relation of dimension, not a new law of force (it is the result of reading it off from known force shapes). The horizontal positions in the figure are schematic; the real range ratios (weak \(\sim\!10^{-18}\text{m}\), strong \(\sim\!10^{-15}\text{m}\)) differ by orders of magnitude. The value of the mediator masses and the mass gap (the origin of \(\sigma\)) are current open problems. — To print, use your browser's "Print" and "Save as PDF" (in the print version the slider and answers are static and hidden).

Print / save as PDF: Ctrl+P (⌘+P on Mac). On screen, move the distance cursor with the slider to read the running dimension D of all four forces at once. Click "Show the answer" to open each solution.