Tunneling That ClicksEpisode 2 / The Sun burns because it tunnels

Heat alone is three orders of magnitude short ── it burns anyway, because there is a way through, up on the exponent

The Sun burns because it tunnels \(k_BT\) at the Sun's centre is 1.3 keV; the proton–proton barrier is 1.4 MeV.
The classical probability of getting over is \(e^{-1083}\) ── a number that never happens anywhere in the universe.
And yet it burns. Moreover, it burns at a single point where two opposing exponentials collide.

Tools you'll need: \(e^{-2S_E/\hbar}\) from Episode 1, the Boltzmann factor from "Temperature That Clicks" Episode 2 The heart of this episode: the Gamow peak, E₀ = (E_G (k_BT)²/4)^(1/3)

Everyone knows the Sun runs on fusion. Put numbers in and you get stuck immediately ── the Sun's centre is about three orders of magnitude too cold to fuse anything. In 1929 Atkinson and Houtermans noticed the contradiction, read Gamow's alpha-decay paper from the year before (Episode 1), and produced the answer: you don't have to go over. Tunnel through. And the story does not end there. Heat says "higher energy is rarer"; tunneling says "higher energy is easier" ── two opposing exponentials collide and squeeze the reaction into a single narrow band of energy. This "Gamow peak" is what decides why stars can burn quietly for ten billion years.

01First, confirm the shortfall

The numbers at the Sun's centre
QuantityValue
central temperature1.5×10⁷ K
measured in energy, \(k_BT\)1.3 keV
Coulomb energy needed to bring two protons within 1 fm1.4 MeV
ratioabout 1100×

A plain ratio, in the style of Episode 1 of "Temperature That Clicks." To get over thermally, the Boltzmann factor (Episode 2 there) gives

$$e^{-1.4\,\mathrm{MeV}/1.3\,\mathrm{keV}}=e^{-1083}\approx 10^{-470}$$

There are about \(10^{57}\) protons in the Sun, so at most \(10^{114}\) pairings. \(10^{-470}\) means it never happens once in the whole history of the universe. Classically, the Sun does not shine.

"If it's too cold, make it hotter" ── but the Sun's central temperature is fixed by its mass and gravity; you cannot move it. In the 1920s this was a genuine crisis. Eddington was convinced the Sun could only be powered by fusion, and the temperature was plainly insufficient. When told to go and find a hotter star, he is said to have replied, "go and find a hotter place."

02The Gamow factor ── getting through without going over

Apply Episode 1's tool directly. The wall is the Coulomb potential \(V(r)=Z_1Z_2e^2/4\pi\varepsilon_0 r\). Put it into \(S_E=\int\sqrt{2m(V-E)}\,dr\) and integrate, and something remarkably clean comes out.

The Gamow factor
$$P(E)\ \approx\ \exp\!\left(-\sqrt{\frac{E_G}{E}}\right), \qquad E_G=2m_rc^2\big(\pi\alpha Z_1Z_2\big)^2$$

\(E_G\) is the Gamow energy, fixed entirely by who the partners are. For two protons it is \(E_G=493\) keV (with \(\alpha=1/137\) the fine-structure constant and \(m_r\) the reduced mass).
The shape is the point ── the larger \(E\), the smaller the exponent, so the easier it is to get through. But it sits under a square root, so the effect is gentle.

Try the typical energy at the Sun's centre, \(E=k_BT=1.3\) keV:

$$\sqrt{493/1.3}=19.5\qquad\Longrightarrow\qquad P\approx e^{-19.5}\approx 3\times10^{-9}$$

\(10^{-470}\) has become \(10^{-9}\). An improvement of 461 orders of magnitude. That happens often enough among the Sun's \(10^{57}\) protons. Episode 1's lesson ── change what is on the exponent and the answer changes by orders ── is what lights the stars.

03Two exponentials collide ── the Gamow peak

Here is the real subject of this episode. A reaction needs two things at once.

What is requiredProbabilityHigher energy means
a proton that fast exists\(e^{-E/k_BT}\)worse (rarer)
it gets close and tunnels\(e^{-\sqrt{E_G/E}}\)better (easier to get through)

Opposite directions. Multiply them and a sharp peak appears at neither extreme but in between.

Locating the peak

Differentiate the exponent of \(\exp\!\left(-\dfrac{E}{k_BT}-\sqrt{\dfrac{E_G}{E}}\right)\) with respect to \(E\) and set it to zero:

$$E_0=\left(\frac{E_G\,(k_BT)^2}{4}\right)^{1/3}$$

At the Sun's centre (\(k_BT=1.29\) keV, \(E_G=493\) keV),

$$E_0=\left(\frac{493\times1.29^2}{4}\right)^{1/3}\ \mathrm{keV}\approx \mathbf{5.9\ keV}$$

So ── fusion in the Sun happens neither at the typical proton energy (1.3 keV) nor at the barrier (1400 keV), but in between, at 5.9 keV. The peak is only about 6 keV wide. Out of not \(10^{23}\) but \(10^{57}\) protons, only the fraction that lands in this narrow window keeps the star shining.

04Try it ── two exponentials and their product

The figure shows the three curves just described. Blue falling to the right is "a proton that fast exists"; red rising to the right is "it tunnels"; and their product is the orange peak. The vertical axis is logarithmic and spans more than 30 orders of magnitude.

Move the temperature slider and the peak shifts while its height changes violently. This is the core of stellar physics ── raise the temperature by 10% and the reaction rate jumps by tens of percent. That steep temperature dependence is what automatically settles a star at one temperature (too hot, it expands and cools; too cool, it contracts and heats).

Figure: proton–proton fusion. Blue = the Maxwell factor e^(−E/k_BT), red = the Gamow factor e^(−√(E_G/E)), orange = their product (the Gamow peak). The vertical axis is logarithmic. Changing the temperature moves the peak's position and height. The Sun's centre is 1.5×10⁷ K
a proton that fast exists probability of tunneling their product = where reactions actually happen

05Which is why stars burn slowly

An unexpected fact. Per unit volume, the Sun's centre is remarkably dim.

Heat sourcepower per unit volume
the Sun's centre (its brightest part)about 280 W/m³
the Sun, averagedabout 0.27 W/m³
a human bodyabout 1000 W/m³
a compost heapa few hundred W/m³

Per unit volume, you generate more heat than the centre of the Sun. The Sun is bright because it is enormous. And that dimness is exactly why the Sun lasts ten billion years ── being hard to tunnel through is not a defect but a lifetime. Without the barrier, all the hydrogen in the universe would have turned to helium in the first few minutes, and there would be no stars, no planets and no living things.

To be exact, there is a second reason for the slowness The Sun's main reaction is \(p+p\to d+e^++\nu\). Look closely: a proton has turned into a neutron ── that is the weak interaction, which is hard to make happen quite apart from tunneling.
So the Sun's slowness is the product of slow tunneling and a slow weak interaction. The average wait for any one proton to react is about nine billion years. That double slowness is why the Sun burns so quietly. Writing "the Sun is slow entirely because of tunneling" would be an overstatement, so let us keep the two separate.

06Why the temperature dependence is so extreme

The height of the Gamow peak goes as \(\exp(-3E_0/k_BT)\). Insert \(E_0\propto T^{2/3}\) and the reaction rate becomes a power of temperature ──

Temperature dependence in stars
$$\varepsilon\propto T^{\nu},\qquad \nu=\frac{\tau-2}{3},\qquad \tau=\frac{3E_0}{k_BT}$$
ReactionE_Gν at the Sun's centreMeaning
pp chain (p + p)493 keVabout 4gentle. This is the Sun
CNO cycle (p + ¹²C)32.9 MeVabout 20ferocious. Heavy stars run on this

A large \(Z\) sends \(E_G\) soaring, pushes the peak to higher energy, and steepens the temperature dependence. That stars a little heavier than the Sun switch to CNO and become short-lived is a direct property of this exponential. A star's whole life is decided by the number on the exponent.

◇ ◇ ◇
The honest line ── what was simplified

Established: the Sun's central temperature and density and \(k_BT\approx1.3\) keV; that the Coulomb barrier is of order an MeV and classically insurmountable; the Gamow factor \(\exp(-\sqrt{E_G/E})\) and the Gamow energy \(E_G=2m_rc^2(\pi\alpha Z_1Z_2)^2\) (493 keV for p–p); the Gamow peak \(E_0=(E_G(k_BT)^2/4)^{1/3}\approx5.9\) keV and its width; the temperature dependence \(\varepsilon\propto T^{\nu}\) with \(\nu\approx4\) for pp and \(\approx20\) for CNO; the application of tunneling to stellar fusion by Atkinson and Houtermans (1929); and the Sun's power per unit volume. All standard stellar physics.

Simplifications: (1) The real rate is written \(\sigma(E)=\dfrac{S(E)}{E}e^{-\sqrt{E_G/E}}\), with the nuclear physics packed into the astrophysical S-factor \(S(E)\). The body treats \(S(E)\) as essentially constant (a good approximation for non-resonant reactions, but it fails when there is a resonance). (2) \(p+p\) involves the weak interaction, so the rate is not set by ease of tunneling alone (as noted in the body). (3) In stellar plasma the surrounding electrons screen the barrier slightly (a few percent correction in the Sun; that screening becomes the protagonist in bonus ①). (4) The derivation of the Gamow peak is a saddle-point approximation and deviates slightly from a Gaussian. (5) The figure idealises a single reaction, non-degenerate and non-relativistic. (6) There was once a "solar neutrino problem" in which only a third of the predicted neutrinos were observed; the cause was neutrino oscillation, not the stellar model, and it was resolved in 2001–02 (the picture in the body is unaffected).

Exercises (solvable with this episode's ideas)
  1. Show with numbers that the Sun does not shine in classical mechanics.
    See the answer
    Barrier 1.4 MeV, \(k_BT=1.3\) keV. The Boltzmann factor is \(e^{-1400/1.3}=e^{-1083}\approx10^{-470}\). With \(10^{57}\) protons there are only \(10^{114}\) pairings, so it never happens once in the history of the universe.
  2. Why does the reaction occur neither at \(k_BT\) nor at the barrier height, but in between?
    See the answer
    Because the two exponentials pull in opposite directions. At low energy "there are plenty of protons but they cannot get through"; at high energy "they could get through but there are none." A narrow window opens where the product is maximal, at \(E_0=(E_G(k_BT)^2/4)^{1/3}\approx5.9\) keV.
  3. Why is the CNO cycle's temperature dependence so much steeper than the pp chain's?
    See the answer
    Carbon has \(Z=6\), so \(E_G\propto(Z_1Z_2)^2\) leaps by more than a factor of 36 (493 keV → 32.9 MeV) and the Gamow peak is pushed to higher energy. That raises \(\tau=3E_0/k_BT\) and hence \(\nu=(\tau-2)/3\). Heavy stars are short-lived because of this exponential.
  4. What would the universe be like if the Coulomb barrier did not exist?
    See the answer
    In the hot dense early universe all the hydrogen would have burned to helium (or beyond). No stars would form, and no heat source lasting billions of years would exist. Being hard to tunnel through is not a defect but the lifetime of the universe.

Episode 2 summaryStars burn on the exponent

\(k_BT\) at the Sun's centre is 1.3 keV; the proton–proton Coulomb barrier is 1.4 MeV ── a factor of 1100 short. The classical probability is \(e^{-1083}\approx10^{-470}\), a number that never occurs once in the history of the universe. Apply Episode 1's tunneling and it becomes \(e^{-\sqrt{E_G/E}}=e^{-19.5}\approx10^{-9}\) ── an improvement of 461 orders. The Sun shines because it tunnels.

More interesting still, heat (higher energy is worse) and tunneling (higher energy is better) are opposing exponentials. Their product peaks sharply in between, and fusion in the Sun happens neither at the average nor at the barrier but in a narrow window at 5.9 keV (the Gamow peak).

And the steepness of that exponential decides a star's life. Rates run from \(T^4\) (pp) to \(T^{20}\) (CNO), so heavy stars burn ferociously and die young. That the Sun is dimmer per unit volume than a human body and still lasts ten billion years is thanks to being hard to tunnel through.

This document is Episode 2 of the "Tunneling That Clicks" series, a reading piece for physics-loving high-schoolers and undergraduates. The Sun's central temperature and \(k_BT\approx1.3\) keV, the size of the Coulomb barrier, the Gamow factor \(\exp(-\sqrt{E_G/E})\) and the Gamow energy (493 keV for p–p), the Gamow peak \(E_0=(E_G(k_BT)^2/4)^{1/3}\approx5.9\) keV, the temperature dependence (about \(T^4\) for pp and \(T^{20}\) for CNO), the application to stellar fusion by Atkinson and Houtermans (1929), and the Sun's power per unit volume are all established stellar physics. That the real cross-section contains the astrophysical S-factor treated here as constant, that \(p+p\) involves the weak interaction so its slowness is not due to tunneling alone, that electron screening in stellar plasma (a few percent) is omitted, that the Gamow peak is a saddle-point approximation, and that the solar neutrino problem was resolved by neutrino oscillation in 2001–02 without affecting the picture here ── all spelled out in the body's "honest line." The figure computes the Gamow peak live in the browser. ── To print, use your browser's "Print" and "Save as PDF" (in the print version the sliders and answers are frozen and hidden). Adjacent episodes: Episode 1, Tunneling is just walking, in imaginary time / Episode 3, Climb over, or slip through / Contents / sister series Temperature That Clicks.

Print / make a PDF: ⌘+P (Ctrl+P on Windows). On screen the temperature slider moves the Gamow peak and changes its height by orders of magnitude. The CNO button switches the partner to carbon so you can see how far the peak gets pushed out. "See the answer" opens each solution.