The equation of motion for the wave ψ ── and why "energy in discrete steps" is the plain consequence of trapping a continuous wave in a box
In Episodes 2 and 3 we looked at the wave function \(\psi\) and at adding up its phases \(S/\hbar\). So how, exactly, does \(\psi\) change shape from moment to moment? The "equation of motion for the wave" that gives this directly is the Schrödinger equation \(i\hbar\,\partial\psi/\partial t=\hat H\psi\). And when you trap this wave in a box, quantum theory's most famous face appears ── energy comes in "discrete steps" (quantization). But there's something we want to stress here. Things become discrete not because the world is discrete. It is exactly the same as a guitar string only sounding at particular pitches (overtones) ── confine a continuous wave with both ends fixed, and only the waves that "fit" get selected, and as a result you get discrete steps. Quantization is a perfectly ordinary consequence of being a wave.
If \(\psi\) is a wave, there must be an equation deciding how the wave spreads. Writing that down by translating the energy relation "kinetic energy + potential energy = total energy" into the language of waves is the Schrödinger equation.
On the left, \(i\hbar\,\partial_t\) represents "energy"; on the right, \(\hat H\) (the Hamiltonian) represents the kinetic + potential energy. The presence of \(i\) and \(\hbar\) is the crux ── thanks to \(i\), the solution becomes an oscillating wave, and the phase spins at the rate \(E/\hbar\) (exactly Episode 1's \(E=\hbar\omega\)). The \(i\) left over in Episode 3 of "Cosmology That Clicks" is this \(i\).
As a special solution, there are waves whose shape doesn't change and whose phase alone spins. This is a state of definite energy (\(\hat H\psi=E\psi\)), and its time dependence is \(\psi(t)=\psi\,e^{-iEt/\hbar}\) ── since the magnitude \(|\psi|^2\) is constant in time, we call it a stationary state. The rate at which the phase spins is \(E/\hbar=\omega\). The higher the state's energy, the faster the phase spins. The "orbits" of an electron in an atom are these stationary states. So can that energy \(E\) take any value at all? ── Confine it, and it cannot.
The simplest confinement ── put an electron in a box of width \(L\) (walls on both sides). Since it can't leave the walls, \(\psi\) must be zero at both ends. This is exactly the same condition as a string fixed at both ends. So the only waves allowed are standing waves with nodes at both ends ── waves where an integer number of half-wavelengths fits exactly.
If n half-wavelengths fit exactly, the wavelength is
$$\lambda_n=\frac{2L}{n}\quad(n=1,2,3,\dots)$$Using de Broglie's p=h/λ (Episode 1) and E=p²/2m gives
$$E_n=\frac{p_n^2}{2m}=\frac{n^2 h^2}{8mL^2}$$Energy can only take the discrete values (\(E_n\propto n^2\)) for \(n=1,2,3\dots\). Even though the wave is continuous, the boundary condition of confinement selects out the allowed waves by an integer \(n\) ── that is quantization. It is precisely the same logic as a guitar string only sounding the fundamental, second harmonic, third harmonic, and so on.
The \(n\) (quantum number) that counts the discrete steps is a unitless integer. Like the inverse-square power \(d-1\) in Episode 5 ("Fields That Click"), or the Yukawa coupling of mass, a physical "count" always shows up as a dimensionless integer or ratio. \(n\) is literally "how many half-wavelengths fit in the box."
The figure below. In a box of width \(L\), we draw the wave \(\psi=\sin(n\pi x/L)\). Use the slider to move \(n\) continuously. Only when \(n\) is an integer does the right end of the wave land exactly at the wall as a node (zero), so it "fits" (green = allowed). Stray from an integer and the right end sticks out past the wall, so it doesn't fit (red = not allowed). The ladder on the right shows the allowed energies \(E_n\propto n^2\).
Even as you turn \(n\) continuously, the only physically allowed values are the rungs of the ladder (integer \(n\)). On top of a world of continuous waves, the boundary condition applies a "discrete sieve" ── this is the true identity of quantization. Shrink the box (small \(L\)) and the spacing of the rungs (\(\propto1/L^2\)) widens, making the quantization stand out. Confine it as small as an atom and the discreteness of the energy levels becomes conspicuous, producing light of fixed colors specific to each atom (spectral lines).
This is what we most want to convey in this episode. The impression that "quantum = the world is discrete (digital)" is not accurate. The Schrödinger equation is the equation of a smooth, continuous wave. Space and time are both continuous, and \(\psi\) varies continuously. Things become discrete only when the wave is confined, because only the fitting modes get selected ── on a continuous foundation, boundary conditions produce discreteness. A free electron with no confinement can take energy continuously (it does not become discrete). Discreteness is not the discreteness of the world, but the consequence of wave + confinement.
The Schrödinger equation \(i\hbar\partial_t\psi=\hat H\psi\), the stationary state \(\psi e^{-iEt/\hbar}\), the quantization of a particle in a box \(E_n=n^2h^2/8mL^2\) and \(\lambda_n=2L/n\), the continuous spectrum of a free particle, the energy levels and emission spectra of atoms, and the fact that quantization comes from the standing-wave boundary conditions (isomorphic to a string's overtones) are all established physics.
However. ① The Schrödinger equation is non-relativistic (\(\beta\ll1\); it doesn't include Episode 1's "story of c"). To reconcile relativity and quantum theory you need quantum field theory (the Dirac equation and so on, SR + QM = "Fields That Click") ── relativity and quantum theory are not "in opposition"; they merge here. ② A real atom is confined not by a box but by the nucleus's Coulomb attraction (in 3D), and its quantum numbers include not just \(n\) but angular momentum and others. The "box" is the simplest model. ③ "Quantization = wave + confinement" is a story about bound states; there is also discreteness, such as spin, that isn't easily reduced to a "wave in space." ④ Whether spacetime itself is discrete or continuous at the Planck scale is unsettled (quantum gravity) ── that is not this episode's topic.
The equation of motion for the wave function \(\psi\) is the Schrödinger equation \(i\hbar\partial_t\psi=\hat H\psi\). Thanks to \(i\), the solution is an oscillating wave, and a stationary state has its phase spinning at \(E/\hbar=\omega\) (Episode 1's \(E=\hbar\omega\)). Trap this wave in a box of width \(L\) and only standing waves with nodes at both ends are allowed; only waves with an integer \(n\) half-wavelengths fitting get selected, and energy becomes discrete, \(E_n=n^2h^2/8mL^2\) ── the same as a guitar's overtones. The quantum number \(n\) is a unitless integer.
The key point is that discreteness (quantization) is not because "the world is discrete." The Schrödinger equation is the equation of a continuous wave, and discreteness is an emergent consequence of the fitting modes being selected when a wave is confined (a free particle is continuous). A continuous waveform and its discrete modes are, like a record and a CD, two views of the same thing, and what connects them is the Fourier transform ── the stage for next episode's uncertainty. "Continuous or discrete" is a matter of description, not of the foundation; what matters is still \(\hbar\).
Print / make a PDF: ⌘+P (on Windows, Ctrl+P). On screen, moving n makes the wave "fit" the box only at integers (green). Click "Show the answer" to open a solution.