Temperature That ClicksEpisode 6 / Temperature is a period in imaginary time

Rotate time 90° onto the imaginary axis and quantum time evolution turns into a statistical weight ── temperature was the circumference of that circle

Temperature is a period in imaginary time Compare \(e^{-iHt/\hbar}\) with \(e^{-H/k_BT}\) and you get \(t=-i\hbar/k_BT\).
That is: the imaginary-time direction is a circle of circumference \(\hbar/k_BT\) ──
at room temperature, one lap takes 25 femtoseconds.

Tools you'll need: Episode 2's Boltzmann factor, exponentials and complex numbers, Episode 9 of "Cosmology That Clicks" The heart of this episode: the imaginary-time period = ℏ/k_BT

So far we have treated temperature as the slope of a sharing of energy. This episode shows a completely different face ── temperature is the reciprocal of the circumference of a circle formed by time's other axis (imaginary time). It sounds outlandish, but what produces it is a startlingly simple comparison. Quantum time evolution is \(e^{-iHt/\hbar}\); the statistical weight is \(e^{-H/k_BT}\). They look almost identical. For the two to agree we need \(t=-i\hbar/k_BT\) ── a purely imaginary time. And this is not a formal game: it carries the physical content that going once around in imaginary time multiplies you by the Boltzmann factor (the KMS condition), it gives another reading of Episode 3's "freezing," and it is the very origin of the Hawking and Unruh temperatures in the finale. It also settles the homework left in Episode 9 of the sister series "Cosmology That Clicks."

01The Wick rotation ── turning by 90° with \(i\)

A quantum state's phase rotates with time: \(e^{-iEt/\hbar}\). It only oscillates; the magnitude never changes.

Now twist time onto the imaginary axis. Set \(t=-i\tau\) with \(\tau\) real:

$$e^{-iE t/\hbar}\ \xrightarrow{\ t=-i\tau\ }\ e^{-E\tau/\hbar}$$

Oscillation has turned into decay. And the decay \(e^{-E\tau/\hbar}\) looks exactly like Episode 2's Boltzmann factor \(e^{-E/k_BT}\).

02Just compare them, and the period drops out

The heart of this episode
$$\underbrace{e^{-E\tau/\hbar}}_{\text{advance }\tau\text{ in imaginary time}}\ =\ \underbrace{e^{-E/k_BT}}_{\text{Boltzmann factor at }T} \qquad\Longleftrightarrow\qquad \boxed{\ \tau=\frac{\hbar}{k_BT}\ }$$

In other words ── advancing \(\hbar/k_BT\) in imaginary time is the same thing as coming to thermal equilibrium at temperature \(T\). This length is written \(\beta\hbar\) (with \(\beta=1/k_BT\), the lead of Episode 2).

Moreover, the quantum partition function \(Z=\mathrm{Tr}\,e^{-\beta H}\) has the form of "start and end at the same place" (a trace), so the imaginary-time direction is a circle with its ends joined. A system with a temperature is one in which one direction of time is a circle of circumference \(\beta\hbar\).

The consequence of that rephrasing is the most interesting part.

One lap in imaginary time multiplies by the Boltzmann factor

Take a state of energy \(E\) once around in imaginary time and it comes back multiplied by \(e^{-E\beta\hbar/\hbar}=e^{-E/k_BT}\).
"Being in thermal equilibrium" = "one lap in imaginary time multiplies by the Boltzmann factor." Stated rigorously this is the KMS condition (Kubo–Martin–Schwinger), and in the modern view it is adopted as the definition of temperature. However complicated the interactions, even where no particle number can be defined, "periodicity in imaginary time" can still be written ── this is the most general definition of temperature there is.

03In orders of magnitude ── room temperature is 25 femtoseconds

The imaginary-time period at room temperature $$\beta\hbar=\frac{\hbar}{k_BT}=\frac{1.055\times10^{-34}}{(1.381\times10^{-23})(300)}=2.5\times10^{-14}\ \mathrm{s}=25\ \mathrm{fs}$$

Episode 1 had us memorise "room temperature \(k_BT\approx25\) meV." That and 25 fs are two sides of a single fact (\(\hbar/25\,\mathrm{meV}=26\) fs). In energy it is 25 meV; in time it is 25 fs ── one and the same mark for the state called room temperature, tied together by the uncertainty relation \(\Delta E\,\Delta t\sim\hbar\).

Temperaturek_BTimaginary-time period ℏ/k_BT
cosmic microwave background, 2.7 K0.23 meV2.8 psa long circle = cold
liquid nitrogen, 77 K6.6 meV99 fs
room temperature, 300 K25 meV25 fsthe reference
the Sun's surface, 5800 K0.50 eV1.3 fs
the Sun's core, 1.5×10⁷ K1.3 keV0.5 asa very short circle = hot
absolute zero0the circle unrolls into a plain straight line

That last row is suggestive ── absolute zero is the state in which the imaginary-time circle has unrolled to infinite length. Turned around: to have a temperature is for one direction of time to be curled up. Episode 1 said temperature is not a property of matter; by this point it starts to look like a property of spacetime. In the finale that intuition becomes literally true.

04Try it ── the thickness of the circle is the temperature

The figure below is the complex time plane. Horizontal is real time (ordinary time), vertical is imaginary time \(\tau\). The top and bottom edges of the strip are the same points, curled there into a cylinder ── so the height of the strip is exactly the period \(\beta\hbar\).

Move the temperature slider and the height of the strip changes. Cool it and the strip grows taller (the circle grows longer); heat it and the strip thins (the circle shortens). The shading inside is the decay \(e^{-E\tau/\hbar}\), and the number on the right is the factor picked up in one lap = the Boltzmann factor. Switch the energy and you can read off whether that state gets thermally excited, as a one-lap factor.

Figure: the complex time plane. Horizontal = real time, vertical = imaginary time τ. The top and bottom edges are identified (a cylinder), and that height is the period βℏ = ℏ/k_BT. Raise the temperature and the strip thins. The shading is e^(−Eτ/ℏ); one lap's worth is the Boltzmann factor
the imaginary-time strip (period βℏ) top and bottom edges = the same points the Boltzmann factor from one lap

05What is it good for ── three dividends

① Episode 3's "freezing" becomes a question of fitting on the circle.
If the imaginary-time direction is a circle of circumference \(\beta\hbar\), the frequencies that can live on it are discrete (like standing waves on a string) ── \(\omega_n=2\pi n/\beta\hbar\). These are the Matsubara frequencies. The first is \(\hbar\omega_1=2\pi k_BT\), which at room temperature is 157 meV. A degree of freedom with a level spacing larger than that does not fit on the circle = it cannot be excited thermally ── Episode 3's freezing by \(\hbar\omega/k_BT\), restated as geometry.

② Statistical-mechanics calculations turn into quantum-mechanics calculations.
A \(d\)-dimensional statistical-mechanics problem can be solved as \(d-1\) spatial dimensions plus one (periodic) imaginary-time dimension ── i.e. as a quantum-mechanical problem. Episode 4 of the sister series "Renormalization That Clicks" dealt with the 2D Ising model; that is equivalent to a 1D quantum spin chain ── one dimension gets transferred. This statistical ↔ quantum correspondence is an everyday computational tool, from lattice gauge theory to condensed matter.

③ "Having a temperature" can be stated geometrically.
This is the bridge to the finale. If the imaginary-time period is the temperature, then conversely ── if the imaginary-time direction of spacetime happens to be curled up for some reason of its own, there is a temperature there. That is exactly what happens for an accelerating observer, and for an observer outside a black hole.

Settling the debt from Episode 9 of "Cosmology That Clicks" Episode 9 of the sister series, "Rotate \(i\) onto the imaginary axis and you get temperature," was precisely this story ── the imaginary-time period simply is the temperature. There it was overlaid on the \(c\cdot t=\)constant expansion to show the universe's temperature falling as \(1/t\).
This episode is the same thing described from the temperature side. Put them together: the universe expanding and cooling is the imaginary-time circle gradually growing longer. The two pictures look quite different; the equations being written are the same.
◇ ◇ ◇
The honest line ── is "imaginary time" a tool or a reality?

Established: that the Wick rotation \(t=-i\tau\) maps the quantum time-evolution operator \(e^{-iHt/\hbar}\) to the statistical weight \(e^{-\beta H}\); that the quantum partition function \(Z=\mathrm{Tr}\,e^{-\beta H}\) can be written as an imaginary-time path integral of period \(\beta\hbar\); that the KMS condition gives a general characterisation of thermal equilibrium states; the Matsubara frequencies \(\omega_n=2\pi n/\beta\hbar\) (for bosons); the correspondence between \(d\)-dimensional classical statistics and \((d-1)+1\)-dimensional quantum systems; and \(\beta\hbar\approx25\) fs at room temperature ── all established physics.

Points to note: (1) Imaginary time is not a "second time that exists." It is a computational construction obtained by analytically continuing the real-time theory; what is observed is always a real-time quantity. After computing in imaginary time you must continue back to real time ── and that reverse continuation is famously ill-conditioned numerically. (2) For fermions the boundary condition in the imaginary-time direction is anti-periodic and the Matsubara frequencies become half-integer (the body treats bosons). (3) The Wick rotation is not always permitted. With time-dependent external fields, out of equilibrium, and in general curved spacetimes, Euclideanisation can be non-unique or simply undefined. (4) The strip height in the figure scales as \(1/T\) but is clipped top and bottom to fit the display (it is not drawn to true scale). (5) "Having a temperature = time being curled up" is a restatement for equilibrium states.

Exercises (solvable with this episode's ideas)
  1. Compare \(e^{-iEt/\hbar}\) with \(e^{-E/k_BT}\). What is \(t\)?
    See the answer
    From \(-iE t/\hbar=-E/k_BT\), \(t=-i\hbar/k_BT=-i\beta\hbar\) ── a purely imaginary time. Its magnitude \(\beta\hbar\) is the period in the imaginary-time direction.
  2. What is absolute zero in this picture?
    See the answer
    \(\beta\hbar=\hbar/k_BT\to\infty\), so the imaginary-time circle unrolls into an infinitely long straight line. The periodicity disappears and you are back to ordinary (thermless) quantum mechanics.
  3. In this episode's language, give the rough energy that "heat cannot reach" at room temperature.
    See the answer
    The lowest frequency that fits on the imaginary-time circle (the first Matsubara frequency) is \(\hbar\omega_1=2\pi k_BT\). At room temperature that is \(6.28\times25\ \mathrm{meV}\approx157\) meV. A level spacing larger than that does not fit on the circle = it is frozen. The geometric version of Episode 3's \(\hbar\omega/k_BT\).
  4. State "having a temperature" geometrically, in one sentence.
    See the answer
    That time's other axis (imaginary time) is a circle of circumference \(\hbar/k_BT\). The shorter the circle the hotter; infinitely long is absolute zero. Conversely, if spacetime's own structure curls imaginary time up, there is a temperature there (Episode 7).

Episode 6 summaryTemperature is the reciprocal of a circle's circumference in imaginary time

Rotate time 90° onto the imaginary axis (the Wick rotation \(t=-i\tau\)) and quantum phase rotation \(e^{-iEt/\hbar}\) turns into decay \(e^{-E\tau/\hbar}\). Simply comparing that with Episode 2's Boltzmann factor \(e^{-E/k_BT}\) gives \(\tau=\hbar/k_BT=\beta\hbar\). Because the partition function is a trace, the ends of imaginary time join up into a circle of circumference \(\beta\hbar\).

The physical content is "one lap in imaginary time multiplies by the Boltzmann factor" ── made rigorous, this is the KMS condition, which in the modern view is used as the definition of temperature. In orders of magnitude, one lap at room temperature is 25 femtoseconds, the same single mark as Episode 1's "25 meV," tied to it by the uncertainty relation. Absolute zero is the circle unrolled into a line.

Three dividends ── (1) Episode 3's freezing translates into "does it fit on the Matsubara circle?" (the first Matsubara energy at room temperature is 157 meV), (2) \(d\)-dimensional statistics turns into \((d-1)+1\)-dimensional quantum mechanics, and (3) if spacetime itself curls imaginary time up, there is a temperature there ── the bridge to the finale.

This document is Episode 6 of the "Temperature That Clicks" series, a reading piece for physics-loving high-schoolers and undergraduates. The correspondence via the Wick rotation between quantum time evolution and the statistical weight; that the quantum partition function can be written as an imaginary-time path integral of period \(\beta\hbar\); the characterisation of thermal equilibrium by the KMS condition; the Matsubara frequencies \(\omega_n=2\pi n/\beta\hbar\); the correspondence between \(d\)-dimensional classical statistical systems and \((d-1)+1\)-dimensional quantum systems; and \(\beta\hbar\approx2.5\times10^{-14}\) s at room temperature ── all established physics. That imaginary time is not a second existing time but a computational construction by analytic continuation (whose reverse continuation to real time is numerically ill-conditioned), that fermions obey anti-periodic boundary conditions with half-integer Matsubara frequencies, that the Wick rotation is not always definable out of equilibrium or in general curved spacetimes, and that the strip height in the figure is clipped for display ── all spelled out in the body's "honest line." ── To print, use your browser's "Print" and "Save as PDF" (in the print version the slider and answers are frozen and hidden). Adjacent episodes: Episode 5, Negative temperature is hotter than infinity / Episode 7, Accelerate, and you get warm / Contents / sister series Cosmology That Clicks (Episode 9) and Renormalization That Clicks.

Print / make a PDF: ⌘+P (Ctrl+P on Windows). On screen the temperature slider changes the height of the imaginary-time strip (= the period), and the buttons switch the energy so you can read the Boltzmann factor picked up in one lap. "See the answer" opens each solution.