Refraction That ClicksEpisode 5 / Refraction and Absorption Are One Function

"An effect does not precede its cause" — that alone binds the real and imaginary parts of the index by an integral

Refraction and Absorption
Are One Function The refractive index is really complex: \(\tilde n=n+i\kappa\), real part refraction, imaginary part absorption.
And the two cannot be chosen independently — causality alone ties them by an integral.
The consequence: anything that bends light must absorb light somewhere.

Tools needed: Episode 1's phasor, complex numbers, a feel for Fourier transforms Core of this episode: Kramers–Kronig

When you turned up the absorption slider on the phasor diagram in Episode 1, the tip of the arrow curled inward. That is this whole episode. The refractive index is really a complex number: the real part says how much the phase is delayed, the imaginary part says how much is absorbed. So far that is just notation. The substance begins here — the real and imaginary parts cannot be chosen independently. Impose one single requirement on physics — "an effect does not precede its cause" — and the two are bound together by an integral. These are the Kramers–Kronig relations. And the consequence is merciless. A material that is perfectly transparent at every frequency and still bends light cannot exist, in principle. Glass is transparent in the visible and has \(n=1.5\) — because glass absorbs ultraviolet.

01Make the index complex

Real part refracts, imaginary part absorbs

Write \(\tilde n=n+i\kappa\) and put it in a plane wave:

$$E=E_0\,e^{i(k_0\tilde n z-\omega t)} =E_0\underbrace{e^{ik_0nz}}_{\text{phase delay}}\ \underbrace{e^{-k_0\kappa z}}_{\text{decay}}\ e^{-i\omega t}$$

Intensity is amplitude squared, so the absorption coefficient is

$$\alpha=2k_0\kappa=\frac{4\pi\kappa}{\lambda_0}$$

In Episode 1's phasor, whether the tip stayed on the circle or spiralled inward was exactly \(\kappa=0\) versus \(\kappa>0\). Refraction and absorption were two components of one complex number from the start.

02Causality — a single-line requirement

Write down the material response. The polarization at time \(t\) depends on every field that has acted so far:

This is the whole requirement
$$P(t)=\varepsilon_0\int_{-\infty}^{\infty}\chi(t-t')\,E(t')\,dt' \qquad\text{with}\qquad \boxed{\ \chi(\tau)=0\quad(\tau<0)\ }$$

The boxed line is causalitya field that has not been applied yet does not affect the present polarization. Nothing more.

But "vanishes for \(\tau<0\)" acquires enormous force under Fourier transform. If \(\chi(\tau)\) is zero for \(\tau<0\), then its transform \(\chi(\omega)\) is analytic in the upper half of the complex \(\omega\) plane — no poles, no cuts. The \(\mathrm{Im}\,\omega>0\) part of \(e^{i\omega\tau}\) suppresses only the \(\tau>0\) side, and that is what makes the integral converge.

And an analytic function is subject to Cauchy's integral theorem. The rest is automatic.

03The Kramers–Kronig relations

The integrals that bind real to imaginary $$n(\omega)-1=\frac{2}{\pi}\,\mathrm{P}\!\!\int_0^\infty\frac{\omega'\,\kappa(\omega')}{\omega'^2-\omega^2}\,d\omega'$$ $$\kappa(\omega)=-\frac{2\omega}{\pi}\,\mathrm{P}\!\!\int_0^\infty\frac{n(\omega')-1}{\omega'^2-\omega^2}\,d\omega'$$

(P is the principal value; Kronig and Kramers, independently, 1926–27.)
Know either one at all frequencies and the other is a calculation. Real and imaginary parts were never independent information.

Core of this episode — there is no way out

Put \(\kappa(\omega')\equiv0\) — absorbing nothing at any frequency — into the first relation.

$$\kappa\equiv0\ \Longrightarrow\ n(\omega)-1=0\ \text{for all }\omega\ \Longrightarrow\ n\equiv1$$

A material that absorbs nothing bends nothing. It is vacuum.
Turned around: every material that bends light is absorbing light at some frequency. A "perfectly transparent lens" cannot exist, in principle.

Even the total amount of absorption is fixed — the sum rule There is a stronger constraint still. Integrate the imaginary part of the dielectric function over all frequencies: $$\int_0^\infty \omega\,\mathrm{Im}\,\varepsilon_r(\omega)\,d\omega=\frac{\pi}{2}\,\omega_p^2, \qquad \omega_p^2=\frac{Ne^2}{\varepsilon_0m_e}$$ The right-hand side contains nothing but the electron number density \(N\). No detail of the material's structure enters.
In other words — the total amount of absorption is set by how many electrons you have. Materials engineering can only choose which frequency to put that absorption at; it cannot reduce it. (The f-sum rule. Episode 3's \(\omega_p\) shows up again.)

04Glass is transparent because glass absorbs

Now look at a real material. Fused silica is transparent in the visible, with enormous absorption on either side.

BandWhat happensGlass
Ultraviolet (\(\gtrsim4\) eV)electrons are excited (band gap)absorbs strongly
Visible (1.6–3.2 eV)too little for electrons, too fast for the latticetransparent (the window)
Infrared (beyond \(\sim\)4 μm)Si–O bond vibrations (phonons)absorbs strongly

The visible transparency is a window between two absorptions. And what Kramers–Kronig says is that the value \(n=1.5\) inside the window is created by the absorptions on either side, with the ultraviolet side dominant.

Put differently

It is not that "glass is transparent, so there is nothing there." Glass's \(n=1.5\) in the visible is the long reach of an absorption sitting out in the invisible ultraviolet.
Press "remove the ultraviolet absorption" on the right of the figure below — the refractive index inside the window drops straight to 1.

05Play with it — one part really does give the other

On the left is a Lorentz oscillator, the simplest model of a bound electron, with \(n\) and \(\kappa\) drawn. The green dots are \(n\) reconstructed by numerically evaluating the Kramers–Kronig integral using \(\kappa\) alone — they should land right on the curve. One part really does give the other.

On the right is a model of glass, with one oscillator in the infrared and one in the ultraviolet. The horizontal axis is log frequency, and the pale band in the middle is the visible window.

Figure: left — n (blue) and κ (violet) for a Lorentz oscillator. The green dots are n reconstructed from κ alone by Kramers–Kronig integration. Right — a "glass" with absorptions in the infrared and ultraviolet. The band in the middle is the visible window, where n is created by the absorptions on either side
index n (real part) absorption κ (imaginary part) n reconstructed from κ by KK
Incidentally — this also fixes the order of the rainbow On the left figure, look below the resonance (which is in the ultraviolet). \(n\) rises with frequency there: normal dispersion. Visible light lives exactly there.
So blue has the larger \(n\) and bends more — which is why a prism throws blue furthest and why the inside of a rainbow is blue. The ultraviolet absorption decides the order of the colours in the sky.
Just inside the resonance, by contrast, \(n\) plunges (anomalous dispersion). That is the region Episode 3 meant when it said the group velocity can exceed \(c\) or go negative.

06The same argument appears all over physics

FieldThe same structure
Optics (this episode)causality → analyticity of \(\tilde n(\omega)\) → refraction and absorption linked
Statistical mechanics (Temperature That Clicks)the fluctuation–dissipation theorem: the imaginary part of the response is dissipation, the real part is reaction. Same causality
Particle physicsdispersion relations and the optical theorem: the imaginary part of the forward amplitude is the total cross-section. S-matrix analyticity reflects causality
Circuitsthe real part (resistance) and imaginary part (reactance) of a passive impedance \(Z(\omega)\) obey the same relation
In one line

The imaginary part is "losing," the real part is "shifting," and causality is the glue between them.

This structure is a cousin of a shape that recurs throughout the sister series — in Tunneling That Clicks, making time imaginary turns a barrier into a valley; here, making frequency complex links absorption to refraction. Both are cases of going out into the complex plane and finding that two apparently separate things are one.

◇ ◇ ◇
The honest line

Established: the complex index \(\tilde n=n+i\kappa\) and \(\alpha=4\pi\kappa/\lambda_0\); that a linear, time-translation-invariant, causal response function is analytic in the upper half plane (Titchmarsh's theorem) and the Kramers–Kronig relations that follow (1926–27); \(\kappa\equiv0\Rightarrow n\equiv1\); the f-sum rule \(\int_0^\infty\omega\,\mathrm{Im}\,\varepsilon_r\,d\omega=(\pi/2)\omega_p^2\); the Lorentz oscillator model and normal/anomalous dispersion; the ultraviolet electronic absorption edge and infrared phonon absorption of fused silica with the visible window between them. All standard physics.

Caveats: (1) Kramers–Kronig assumes a linear, time-translation-invariant, causal, passive response. It does not apply in this form to nonlinear optics at high intensity or to time-varying media. (2) The derivation assumes \(\chi\to0\) as \(\omega\to\infty\). In a conductor \(\varepsilon\) diverges as \(\omega\to0\), so one must work with \(\sigma\) instead of \(\varepsilon\), or otherwise handle the pole. (3) "Transparent means it does not refract" is an idealised statement. What actually follows is "if there is no absorption at any frequency then \(n\equiv1\)"; a band in which absorption is below the measurement floor can perfectly well have \(n\neq1\) — and the point of the text is that a different band's absorption is producing that \(n\). (4) The "glass" on the right is a two-oscillator model, not a reproduction of silica's optical constants. The resonance positions and strengths were chosen to give \(n\approx1.5\) in the visible, for teaching. (5) The KK reconstruction on the left integrates numerically over a finite range (\(\omega'\le40\,\omega_0\)), so there is a small truncation error in principle. (6) The \(N\) in the sum rule is the total electron density including core electrons, and is not a quantity you can verify by looking at the visible region alone.

Exercises
  1. Sketch why causality implies analyticity.
    Show answer
    If \(\chi(\tau)\) is zero for \(\tau<0\), the Fourier transform reduces to \(\int_0^\infty\chi(\tau)e^{i\omega\tau}d\tau\). For \(\mathrm{Im}\,\omega>0\), \(e^{i\omega\tau}\) is a damping factor, the integral converges, and \(\chi(\omega)\) is analytic in the upper half plane. Apply Cauchy's theorem on a closed contour in that half plane and the principal-value relations between real and imaginary parts (KK) drop out.
  2. Show that a material which absorbs nothing also refracts nothing.
    Show answer
    Put \(\kappa\equiv0\) into \(n(\omega)-1=\frac{2}{\pi}\mathrm{P}\int_0^\infty\frac{\omega'\kappa(\omega')}{\omega'^2-\omega^2}d\omega'\) and the right-hand side is identically zero. So \(n=1\) at every \(\omega\) — that is vacuum. Conversely, anything that refracts is absorbing somewhere.
  3. What causes glass to have \(n=1.5\) in the visible?
    Show answer
    The electronic absorption in the ultraviolet (plus the weaker phonon absorption in the infrared). Absorption is essentially zero inside the window, yet \(n\neq1\), because the KK integral reaches out and picks up absorption from other bands. Remove the ultraviolet oscillator in the figure and \(n\) in the window falls to nearly 1. Glass does not refract despite being transparent; it refracts because it absorbs where you cannot see.
  4. Say in this episode's language why a prism bends blue more.
    Show answer
    Visible light sits below the ultraviolet resonance, where \(dn/d\omega>0\) (normal dispersion). Blue is at higher frequency, hence closer to the resonance, hence larger \(n\) — so it bends more. The order of colours in a rainbow is decided by an ultraviolet absorption. Just inside the resonance, anomalous dispersion makes \(n\) plunge, and that is Episode 3's "group velocity above \(c\)" region.

Episode 5 summaryCausality is the glue between real and imaginary

The refractive index is complex, \(\tilde n=n+i\kappa\): real part phase delay (refraction), imaginary part decay (absorption, \(\alpha=4\pi\kappa/\lambda_0\)). And the two cannot be chosen independently. From one line — "an effect does not precede its cause," \(\chi(\tau)=0\) for \(\tau<0\) — \(\tilde n(\omega)\) becomes analytic in the upper half plane, and Cauchy's theorem forces the Kramers–Kronig relations.

The consequences are merciless. Put \(\kappa\equiv0\) in and you get \(n\equiv1\): a material that absorbs nothing bends nothing. And the f-sum rule \(\int_0^\infty\omega\,\mathrm{Im}\,\varepsilon_r\,d\omega=(\pi/2)\omega_p^2\) says that the total absorption is fixed by the number of electrons. You can move it in frequency; you cannot reduce it.

So — glass has \(n=1.5\) in the visible because glass absorbs ultraviolet. The visible transparency is a window between the ultraviolet and infrared absorptions, and the index inside the window is the shadow of an absorption you cannot see. Remove the ultraviolet oscillator in the figure and \(n\) drops straight to 1. The same structure appears in the fluctuation–dissipation theorem, in the optical theorem of particle physics, and in passive circuit impedance — the imaginary part loses, the real part shifts, and causality is the glue.

This document is Episode 5 of the "Refraction That Clicks" series, a reading for physics-loving high-schoolers and undergraduates. The complex refractive index and absorption coefficient, upper-half-plane analyticity of a causal response function (Titchmarsh's theorem), the Kramers–Kronig relations (1926–27), \(\kappa\equiv0\Rightarrow n\equiv1\), the f-sum rule, the Lorentz oscillator and normal/anomalous dispersion, and the ultraviolet and infrared absorptions of fused silica are all standard physics. That KK presupposes a linear, time-translation-invariant, causal and passive response, that conductors need special handling, that "transparent means it does not refract" is an idealised statement, that the "glass" in the figure is a two-oscillator teaching model rather than silica's optical constants, that the KK reconstruction is a finite-range numerical integral, and that the sum rule's \(N\) is the total electron density including core electrons, are all stated in "The honest line" above. — To print, use your browser's Print and "Save as PDF" (sliders freeze and answers are hidden in the print version). Neighbours: Episode 4, Reflection Comes from Mismatch / Episode 6, Stopping Light / Contents / sister series Temperature That Clicks · Fields That Click.

Print / PDF: ⌘+P (Ctrl+P on Windows). On screen, move γ on the left and watch the green dots (n reconstructed from κ) stay on the blue curve. Press "remove the UV absorption" on the right and the refractive index in the visible window falls to 1. "Show answer" reveals the solutions.