Episode 9: force is the connection of a local symmetry → Episode 10: space is stamped into the “shape” of that force
Newtonian gravity is \(1/r^2\). The Coulomb force is also \(1/r^2\). They’re completely different forces, yet they weaken with distance in exactly the same shape. Is this a coincidence? Through Episode 9 we peeled back “what force is and why it exists”; this time we peel back the shape of force (its dependence on distance). And the surprise is this — \(1/r^2\) is not a property of force itself, but the fingerprint of our space being “three-dimensional.” If space were two-dimensional it would be \(1/r\); four-dimensional, \(1/r^3\). The dimension of space is engraved into the shape of force.
Let’s draw the force that gushes from a point as field lines spreading out radially. The total number of field lines coming out of the source is not lost or gained along the way (it is conserved). How densely these lines pierce a sphere at distance \(r\) — that is the strength of the force at that place. The surface area of a sphere is \(4\pi r^2\). Since we divide the same number of lines by a larger area,
Strength of force = density of field lines = total number ÷ area of the sphere
$$F \propto \frac{\text{constant}}{4\pi r^2}\ \propto\ \frac{1}{r^2}$$Move away and the sphere’s surface grows as \(r^2\), so the same field lines are diluted by that much. Hence \(1/r^2\). It’s not that force “decides to weaken with distance” but that it’s simply diluted over an expanding area. For both gravity and electricity, field lines gush from a source and spread into three-dimensional space in the same way. That’s why they come out to the same \(1/r^2\).
This is the crux. The “2” in \(1/r^2\) came from the sphere’s area growing as \(r^2\). So — if the dimension \(d\) of space were different, the size of the “surface” that spreads becomes \(r^{d-1}\). So the force is \(1/r^{d-1}\). The dimension turns straight into the exponent.
2D: what spreads is the circumference (\(\propto r\)) → \(F\propto 1/r\)
3D: what spreads is the sphere’s surface (\(\propto r^2\)) → \(F\propto 1/r^2\) (our world)
4D: what spreads is the 3-sphere (\(\propto r^3\)) → \(F\propto 1/r^3\)
In the figure below, change the dimension of space and watch how the shape of force (and the way field lines dilute) changes. Only when \(d=3\) is it \(1/r^2\) — the reason we live in an inverse-square world is that space is three-dimensional.
The conclusion of Episode 10. The shape \(1/r^2\) is not a property intrinsic to force but the fingerprint of the fact that space is three-dimensional. Gravity and electricity share the same shape because both dilute their field lines in the same three-dimensional space. In Episode 5 we saw “gravity is geometry,” but here, more plainly — for any force, the geometry (dimension) of space is stamped into its distance dependence. This is another appearance of the backbone: force is a relationship that has meaning only on the stage called space.
\(1/r^2\) holds under the conditions that the carrier is massless, space is a uniform three dimensions, and the range is far. At short range other effects come into play (the valley of the interatomic potential in Episode 2 is not \(1/r^2\)). The strong force has a special carrier behavior and does not become inverse-square (Episode 11). And “if extra dimensions are curled up small, gravity might deviate from \(1/r^2\) at very short range” — this is being searched for experimentally, and so far the inverse square has not been broken down to below a millimeter.
The “field lines” and “spreading surface” in the figure are a schematic showing the relationship between dimension and the shape of force; they are not a rigorous depiction of higher dimensions (a 4D “surface” can’t be drawn, so it’s represented conceptually).
The field lines gushing from a point source conserve their total number and dilute over a sphere at distance \(r\) (area \(4\pi r^2\)). Hence the force is \(1/r^2\). Gravity and electricity share the same shape because their field lines spread in the same three-dimensional space. In general, in \(d\) dimensions the spreading surface is \(r^{d-1}\), so \(F\propto 1/r^{d-1}\). In 2D, \(1/r\); in 4D, \(1/r^3\). The shape of force was the fingerprint of the dimension of space.
Tie it to Episode 6, and the inverse square is the package “massless carrier + 3D + long range.” Force is a relationship that has meaning only on the stage of space, and the geometry of space is engraved into its distance dependence — another “geometry reflected in force,” following on from Episode 5’s “gravity = geometry.” Next time, it’s the turn of the one force where this inverse-square common sense is broken: the strong force.
Print / save as PDF: ⌘+P (Ctrl+P on Windows). On screen, the slider lets you see how the shape of force changes as you change the dimension of space. “See the answer” opens each solution.